What alkyl halide(s) are needed to prepare the following ketone by the acetoacetic ester synthesis?

The acetoacetic ester synthesis is a method required for the conversion of ethyl acetoacetate into a ketone having one or two alkyl groups on the -carbon. It is a 3-step process deprotonation reaction that takes place first, followed by alkylation with the alkylating agent, and the last step is hydrolysis and deprotonation.

what alkyl halides are needed to prepare the following ketone by the acetoacetic ester synthesis?

What alkyl halide(s) are needed to prepare the following ketone by the acetoacetic ester synthesis?

What alkyl halides are needed to prepare each ketone using the acetoacetic ester synthesis?


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Problem 26 Problem 27 Problem 28 Problem 29

Video Transcript

This is the answer to Chapter 23. Problem number 27 Fromthe Smith Organic chemistry textbook. Ah, this problem asks us what alcohol? Hey, Allied's air needed to prepare each key tone using the aceto acetic Esther synthesis. Um, and so basically, in order to answer that in each of these three key tones, we need to locate the Alfa Carbon. Um, and then any alcohol groups that are on that Alfa Carbon are going to be from alcohol highlights. And so in a now we have our carbon You'll, um And so this will be the Alfa Carbon. Um, And so there is an Esther group. Our Esther. There's an ethel group on that Alfa Carbon until the alcohol hail ID from which that other group comes. I would be, um, Ethel. And I'll just use bro my for each of these. So it'll be Ethel bromide. Okay, um and so that's essentially what we have to do for the other two as well. So a and B Alfa carbon against circled in green. Um, And again, we have Ethel, uh, groups. This time we have two of them s so you can say to equivalents of ethyl bromide. Okay, Um, and then for part C now we can do the same thing. So this is our Alfa Carbon. Ah. And so we actually have two Alka groups, Um, on the south of carbon. So again, we have an ethel group. Um, and then we have a beautiful group as well. Ah, And so, um, this would come from, uh, ethyl bromide. Ah, and beautiful bromide. Okay, so that's all that there is to this problem again. It's just a matter of identifying the Alfa Carbon on, then, recognizing that any alco groups that are substituted onto that Alfa Carbon came from alcohol hail IEDs on. So just just taking the alcohol chains and, you know, working backwards and making the hairline. Ah. And so that is the answer to Chapter 23. Problem number 27.

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